Boolean Function Using NAND - Edubirdie

University:
Santa Fe College
Course:
PHY 2048 | General Physics 1 with Calculus
Academic year:

2024
Views:

178

Pages:

4
Author:

Jabin F.

# Boolean-function using NAND Basic 2-input minimum no. 7OF NAND foat = a fout = a fout = a #1. f= a+b using minimum no. of 2.- input NAND 274 NAND f= a+b I-NAND 3-NAND #2. F = a+b+c using minimum no. of 2-input NAND- f= a+b+c 6-NAND += xyz using minimum no of two input NAND poxyž= fout 'S-NAND #4 f= ab+cd using minimum no. of two ↓ imput NAND. we prefer NAND designing. Do 3- NAND #⑤ f= ab+64+ef using minimum no. of two mput NAND. 6- NAND ⑦f a+ab =(a+b)→OR 3 NAND atta-o 6-0 x+y 3. NAND fout wuey Based on lock out problem. If initial state of ФФ, 01 What the op after th CLK CLK

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