Practical diode circuit!- (1) Find. I SVO Gie drode is FB replaced. by V VV Gie = 201 GIE Vo I = 20- VrGe 19.8 MA (11) Find IVO +12V Vo=12-Vvsi Vrove 12-0.70.2. Si Gre I. Vo = 5-6K = = 1.98 MA 5.GK (1) Find IV +lov 4.7 KR SI I = 5+10-0.7 4.7K +2.2K 2.07 MA 4.72 0. -5v Vo I (2-2k)-5' 2.07m 2-2-5 -0.45 volt (IV) Find I Since E E2 2.2 ΚΩ UB IS FB Conducting E₁ = 20V → BS IS RB $0.0 I = E-E-Vvsi 6.95 MA 20-4-0.7 (v) Find I R₁ =3.3K2 VR, Vrs 0.7V I = VR = 07 R 3.3k 0.212 MA 201 R2=5.6k2. KVL to Ist mesh 20 = V + V + IR₂ 0.71 3.3-2 20 = => 0.7 +0.7 +12 (5.6k) I = 3.32 MA 2 20 5.6KR 3.109 MA (vi) Find Vo Vo 10- VIGE 10-0.2 9.8V + 10 V Ge is conducting because of smaller cutting voltage.