Concept of Sop & pos using truth table-
a
D
fout
sop
Representation
00
10
21
0
371
0
a
b b
foutpos
000
1
10
1
2
0
0
3
1
1 = 6
OR OF AND SOP fout = a+a.b
0=
1 = a
1= b
fout=
Ams
fsop = 2m (0,1)
Representation
a
b
0 =
1 = a
Fout a+ b.Б
fpos = TM(2,3)
Fout = a
Fout = (a+b)(a+b) (AND OF OR)
fsop = (AND Gate)
I ov fsop = 2xy+0.1
1 IV fpos = (2x+y) (21+7) (x+4) = fpos 21.(x+y)