Reaction Energy Gizmo Answer Key

Name: Dahlia Woodard Date: 05-08-2022 Student Exploration: Reaction Energy Directions: Follow the instructions to go through the simulation. Respond to the questions and prompts in the orange boxes. Vocabulary: calorimeter, chemical bond, endothermic, enthalpy, exothermic, Hess’s law Prior Knowledge Questions (Do these BEFORE using the Gizmo.) 1. Two magnets are stuck together. What might you have to do to get them to separate? To separate them, you would have to exert force and energy. 2. Suppose you held two magnets a short distance apart, then let go. What would happen? Due to their mutual attraction, the two magnetics would move towards one another and become bonded. 3. Think about the magnets in terms of energy. In which case do you increase the potential energy of the magnets? In which case do you increase the kinetic energy of the magnets? Use a more magnetic material if you want to boost the magnetic potential energy. However, you can employ more fields to boost the magnetics' kinetic energy. Gizmo Warm-up Just like magnets, atoms of different elements are attracted together to form chemical bonds. Breaking these bonds requires energy. When a new bond forms, energy is released and temperatures rise. In the Reaction Energy Gizmo, you will explore how the energy of chemical bonding relates to temperature changes that occur during chemical reactions. To begin, check that Reaction 1 and Forward are selected. In this reaction, hydrogen (H2) and oxygen (O2) react to form water (H2O). The reaction takes place inside a device called a calorimeter. Inside the calorimeter, a small chamber holds the reactants. The rest of the calorimeter is filled with water. 1. Click Play ( ). What happens? Atoms of hydrogen and oxygen were floating around in the container. The oxygen atom and hydrogen atom collided to form H20 (water). Only H20 atoms remained at that time. 2. How does the temperature change? It rises from 21 to 27.4 degrees Celsius. Activity A: Energy of chemical bonds Get the Gizmo ready: ● Check that Reaction 1 and Forward are selected. ● Select the INVESTIGATION tab. Introduction: The heat energy stored in a chemical system is called the enthalpy (H) of the system. When atoms are joined by a chemical bond, energy must be added to pull them apart. This increases the enthalpy of the system. When a chemical bond forms, energy is released as shared electrons move into lower-energy orbitals. This causes the enthalpy to decrease. Question: How can you predict how much energy is released in a chemical reaction? 1. Predict: In the warm-up activity, you observed how the reaction inside the chamber affected the temperature of the surrounding water. Based on what happens to the surrounding water, do you think heat energy (enthalpy) is absorbed in the reaction or released? Explain. It is released since the heat increased inside the container 2. Observe: In the Gizmo, the energy required to break a chemical bond is modeled by placing a molecule into a set of mechanical claws. Place one of the hydrogen (H2) molecules between the claws, and press Break bond. A. What happens? The hydrogen bond was broken as the claws pulled apart. B. Look under the Energy absorbed column of the table. How much energy was required to break this bond? 436 kj/mol Note: The energy is given here in units of kilojoules per mole (kJ/mol). This is the energy, in kilojoules, required to break all of the H–H bonds in one mole of H2 gas. C. Remove the hydrogen atoms from the claws and then break apart the other H–H molecule. What is the total energy absorbed so far? 872 kj/mol 3. Measure: Notice that the oxygen atoms are connected by a double covalent bond. This is because the oxygen atoms share two pairs of electrons. Place the oxygen molecule in the claws and press Break bond. A. How much energy is required to break the first O–O bond? 349 kj/mol B. Press Break bond. How much energy is needed to break both bonds? 495 kj/mol C. What is the total energy required to break up two moles of H2 molecules and one mole of O2 molecules? 1367 kj/mol 4. Create: Remove the two oxygen atoms from the claws. Now the claws disappear and you see a template for creating a water molecule. Drag an oxygen and a hydrogen atom into the template. (If necessary, use the Key on the right-hand side as a reference.) A. Click Create bond. What happens? A bond between Hydrogen and oxygen is formed but it is incomplete B. The “jiggling” animation you see represents the release of kinetic energy that occurs when a bond is formed. How much energy was released? 463 C. Drag another hydrogen molecule into the template and click Create bond to make a water molecule. What is the total energy released so far? 926 D. Drag the first water molecule away from the template, then use the Gizmo to create a second water molecule. What is the total energy released now? 1852 kj/mol 5. Calculate: Compare the energy absorbed in breaking up the molecules to the energy released when new bonds are formed. A. In this reaction, was more energy absorbed or released? Released B. How does this relate to the change in temperature observed for this reaction? The temperature of the surroundings rose as the heat was discharged. C. The change in enthalpy (∆H) of the system is equal to the total energy absorbed minus the total energy released. What is the ∆H value for this reaction? 485 Compare this value to the Theoretical ∆H listed on the right side. 6. Draw conclusions: The experimental ∆H value was determined by measuring how much heat the reaction produced inside the calorimeter. This is calculated based on the temperature change of the reaction, the amount of water inside the calorimeter, and the specific heat of the calorimeter. Compare the theoretical change in enthalpy to the experimental value. Are these values close? In an open experiment, heat loss may be the reason why the two values are only one number apart. or another type of human error. Get the Gizmo ready: Activity B: Reaction direction ● Select the Reaction tab. ● With Reaction 1 selected, choose Reverse. Introduction: Reactions that emit heat energy are called exothermic reactions. In an exothermic reaction, more heat energy is released by the formation of bonds than is absorbed in the breaking of bonds. In an exothermic reaction, the temperature of the surroundings will increase and the enthalpy of the system will decrease as energy is emitted from the system. In an endothermic reaction, more heat energy is absorbed in the breaking of bonds than is released in the formation of bonds. The temperature decreases and the enthalpy increases. Question: How can you predict the direction of a chemical reaction? 1. Observe: Notice that in the reverse reaction, the container is filled with water molecules. A. Click Play. What happens? Nothing B. Did the temperature change? No C. Is there any evidence that a reaction took place? No Explain. There were no temperature changes or variations in bond formation, nor were there any chemical alterations. 2. Investigate: Switch to the INVESTIGATION tab. Use the claws to break up the two water molecules, and then form two hydrogen molecules and one oxygen molecule. A. How much energy was absorbed in breaking up the water molecules? 1852 kj/mol B. How much energy was released in forming the product molecules? 0 C. What is the total enthalpy change in the system? 0 D. Based on this result, is this reaction exothermic or endothermic? endothermic Explain. the reaction absorb energy more it release Most endothermic reactions do not occur unless there is a continuous input of energy. For example, water molecules can decompose into hydrogen and oxygen gas by adding a salt and passing an electrical current through the water. 3. Investigate: Select Reaction 2. On the INVESTIGATION tab, go through the reaction in both the forward and reverse directions. State the energy absorbed, energy released, and theoretical ∆H value in each direction: Direction Energy absorbed Energy released Theoretical ∆H Forward 2144 926 -211 Reverse 2347 1072 0 What do you notice about the theoretical ∆H values in the forward and reverse directions? One is in the negative 200s and the other is zero, so they are very different. 4. Predict: Based on your findings, do you think Reaction 2 is more likely to occur in the forward or reverse direction? Explain. Reverse I think the reaction is more likely to be in the opposite direction because there was no reaction when it was moving ahead. 5. Test: Select the REACTION tab and test your prediction by running the reaction in the forward and reverse directions. Describe your findings. In the forward direction, nothing changes, but in the reverse direction, the temperature rises and new products are generated. When the reaction occurred, how did the theoretical ∆H value compare to the experimental value? It is the same 6. Investigate: On the INVESTIGATION tab, go through the remaining reactions, in either direction. (You will only need to look at each reaction once.) Fill in the table, then predict if the reaction will proceed in the forward or reverse directions. Reaction Direction Theoretical ∆H Forward or reverse? 3 Forward 1798 Reverse 4 Forward 13557 Reverse 7. Test: Test your predictions on the REACTION tab. What did you find? Both reactions were carried out in reverse to produce the desired results. Activity C: Bond enthalpy Get the Gizmo ready: ● Select Reaction 3 and Reverse. ● Select the INVESTIGATION tab. Introduction: Each chemical bond has a “bond enthalpy” that describes how much energy is absorbed to break a bond and how much energy is released when the bond is formed. (These values are the same.) A chart of bond enthalpies for some common bonds is shown below. Bond C–H C–C C=C C=O Enthalpy (kJ/mol) 413 348 614 799 Bond O–H O=O O–S O=S Enthalpy (kJ/mol) 463 495 265 523 Bond H–H N–H N≡N S–S Enthalpy (kJ/mol) 436 391 941 266 Question: How can you use bond enthalpy to predict the total enthalpy change of a chemical reaction? 1. Calculate: Consider the reaction CH4 + 2O2 → CO2 + 2H2O. A. In the reactants, how many C–H bonds are there? 4 B. Using the chart above, what is the total bond enthalpy of these bonds? -74.4 C. How many O=O bonds are there? 1 D. What is the total enthalpy of these bonds? 0 E. What is the total bond enthalpy of the reactants? -74.4 F. Do the same calculation for the products of the reaction, CO2 + 2H2O. Carefully count how many of each bond there is, and consider whether bonds are single or double bonds. Show your work and list the total bond enthalpy of the products below. The following tests were conducted using textbook values. (-635.3) -(-74.4)=-50.9 Total bond enthalpy of products: -635.3 G. Based on the enthalpy of the reactants and products, what is the ∆H value for this reaction? (Recall that ∆H = energy absorbed – energy released.) -560.0 H. Use the Gizmo to check your results, and correct any errors if necessary. Enthalpy (kJ/mol) 413 348 614 799 Bond C–H C–C C=C C=O Bond O–H O=O O–S O=S Enthalpy (kJ/mol) 463 495 265 523 Enthalpy (kJ/mol) 436 391 941 266 Bond H–H N–H N≡N S–S 2. On your own: Using the chart above, predict the enthalpy change for the following reactions. Show your work. A key of all relevant molecule structures is shown on the right. A. N2 + 3H2 → 2NH3 Total ∆H: -137.7 B. 8SO2 → S8 + 8O2 Total ∆H: -2374.4 C. C2H4 + 3O2 → 2CO2 + 2H2O N2: N≡N H2: H–H NH3: Exothermic or endothermic: Endothermic SO2: O=S–O S8: 8 S–S bonds O2: O=O Exothermic or endothermic: Endothermic O2: O=O CO2: O=C=O H2O: H–O–H C2H4: Total ∆H: -1081.3 Exothermic or endothermic: Endothermic 3. Analyze: In all of the reactions you investigated today, did it make any difference in which order you broke bonds or formed bonds? Yes Explain your answer. The other causes a reaction with new products whereas the first did nothing. Understanding which one emits/absorbs heat and what type of response something is is crucial for understanding its chrematics. According to Hess’s law, the total enthalpy change for a reaction is simply the sum of all of the individual enthalpy changes in the reaction. The order in which you add these enthalpy changes does not matter.