University:
Augusta University
Course:
CHEM 1441 | General Chemistry
Academic year:

2019
Views:

219

Pages:

4
Author:

Edgar Rowe

Lewis structures worksheet Complete in the following table: Group: IA IVA VA VIA VIIA Element: H C N O F/Cl/Br/I # valence electrons: 1 4 5 6 7 Normal # covalent bonds: 1 4 3 2 1 For the following neutral molecules, calculate the total number of valence electrons and draw the correct Lewis structure. (For neutral molecules, it’s okay to assume the normal numbers of covalent bonds apply and that the central atom is the first non-H element in the formula.) 1. F2 7 + 7 = 14 ve total 4. CH 4 4 + 4(1) = 8 ve total 2. O2 6 + 6 = 12 ve total 5. CH 3Cl 4 + 3(1) + 7 = 14 ve total 3. N2 5 + 5 = 10 ve total 6. CH 2Cl2 4 +2(1) + 2(7) = 20 ve total 7. COCl2 6 + 4 + 2(7) = 24 ve total 11. CH 3OH 4 + 4(1) + 6 = 14 ve total 8. HCN 1 + 4 + 5 = 10 ve total 9. NOBr 5 + 6 + 7 = 18 ve total 10. C2 H2 2(4) + 2(1) = 10 ve total 12. CH 3COOH (The formula gives you hints about the structure – use the normal number of bonds to complete it.) 2(4) + 4(1) + 2(6) = 24 ve total For the following polyatomic ions, write the ion’s name, calculate the number of total valence electrons (being sure to take the charge into account) and draw the correct Lewis structures. (Remember, for polyatomic ions, the normal number of covalent bonds may not always apply! Complete the structure by following the octet rule and making sure the correct total number of valence electrons are showing.) 13. SO42− Name: sulfate 6 + 4(6) + 2 = 32 ve total 2− 14. SO3 Name: sulfite 6 + 3(6) + 2 = 26 ve total 17. ClO − Name: hypochlorite 7 + 6 + 1 = 14 ve total 18. ClO 2− Name: chlorite 7 + 2(6) + 1 = 20 ve total 19. ClO 3− Name: chlorate 7 + 3(6) + 1 = 26 ve total 15. NO3− Name: nitrate 5 + 3(6) + 1 = 24 ve total 20. ClO 4− Name: perchlorate 7 + 4(6) + 1 = 32 ve total 16. NO2− Name: nitrite 5 + 2(6) + 1 = 18 ve total 21. PO43− Name: phosphate 5 + 4(6) + 3 = 32 ve total 22. CO 32− Name: carbonate 4 + 3(6) + 2 = 24 ve total 23. CN − Name: cyanide 4 + 5 + 1 = 10 ve total 24. NH4+ Name: ammonium 5 + 4(1) – 1 = 8 ve total