University:
Bradley University
Course:
MTH 109 | College Algebra
Academic year:

2021
Views:

64

Pages:

2
Author:

segolhandworked

Algebra 2 Name: ID: 1 Assignment Date: Period: Solve each triangle. Round answers to the nearest tenth. 1) B = 180 - 90 - 34 = 56 c² = 20² + 18² c = √724 ≈ 27 tan B = 18/20 sin 34 = a/11 a = 11 * sin 34 ≈ 6.15 cos 34 = b/11 b = 11 * cos 34 ≈ 9.12 2) tan A = 20/18 A = tan⁻¹(20/18) ≈ 48° 3) B = 180 - 90 - 46 = 44 tan 46 = 10/b b = 10 / tan 46 ≈ 9.66 sin 46 = 10/c c = 10 / sin 46 ≈ 13.4 4) tan 46 = 3.1/a a = 3.1 / tan 46 ≈ 3.1 sin 46 = 3.1/c c = 3.1 / sin 46 ≈ 4.37 5) B = 180 - 90 - 50 = 40 tan 50 = b/14 b = 14 * tan 50 ≈ 16.2 sin 50 = b/c c = 14 / sin 50 ≈ 18.52 6) B = 180 - 90 - 21 = 69 tan 69 = b/18 b = 18 * tan 69 ≈ 46.8 sin 69 = b/c c = 18 / sin 69 ≈ 19.3 7) B = 180 - 90 - 21 = 69 cos 21 = b/18 b = 18 * cos 21 ≈ 16.8 sin 21 = a/18 a = 18 * sin 21 ≈ 6.45 In each problem, angle C is a right angle. Solve each triangle rounding answers to the nearest tenth. 9) b = 20, m∠B = 23° 10) m∠A = 22°, b = 8 11) a = 7, m∠A = 41° 12) a = 4, b = 3 13) b = 12, a = 20 14) m∠A = 33°, c = 5.7 15) c = 16, b = 8 16) m∠B = 64°, a = 16