Combined Gas Law Worksheet Boyle's Law and Charles' Law can be combined together to make.... THE COMBINED GAS LAW! P1V1 P2V2 T1 T2 Use the combined gas law to solve the following problems: V1P1T2V2P2T1 V1T2=V2T1 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? V = 30L 2312300 = V. 14200 2) A gas takes up a volume of 17 liters, has a pressure of 2.3 atm, and a temperature of 299 K. If I raise the temperature to 350 K and lower the pressure to 1.5 atm, what is the new volume of the gas? V = 31L 17 2.3 350k = V2 1.5 * 299 3) A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas? P2.5atm 28P1308-342*318 4) A gas has a temperature of 14 °C, and a volume of 4.5 liters. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas? V=4.7L 4.5*302 V2287 5) If I have 17 liters of gas at a temperature of 67 °C and a pressure of 88.89 atm, what will be the pressure of the gas if I raise the temperature to 94 °C and decrease the volume to 12 liters? P= 140atm 1788.9 36712 P2340 6) I have an unknown volume of gas at a pressure of 0.5 atm and a temperature of 325 K. If I raise the pressure to 1.2 atm, decrease the temperature to 320 K, and measure the final volume to be 48 liters, what was the initial volume of the gas? V = 1201 V10.532048*1.2*325 7) If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will be the volume of the gas if I decrease the pressure to 45 atm and decrease the temperature to 750 K? V = 30L 2178750 V2*45*900 8) If I have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0°C, what will be the temperature of the gas if I decrease the volume of the gas to 2.4 L and decrease the pressure to 3.0 atm? T = 160 = K 2.9L 5.0 T2 = 2.4L 3.0 323 9) I have an unknown volume of gas held at a temperature of 115 K in a container with a pressure of 60.0 atm. If by increasing the temperature to 225 K and decreasing the pressure to 30.0 atm causes the volume of the gas to be 29 liters, how many liters of gas did I start with? V = 7.4L V1602252930115