University:
California State University, Northridge
Course:
MATH 150B | Calculus II
Academic year:

2023
Views:

289

Pages:

3
Author:

nadiascoot22

PIKIM T-GARCA BSADE 2-1 PROBLEM SET 1 Given Vo Omis Vc 125 A= 0.0202 Ac 56-10t Solution a= 50- ot 101-09 = dv at V= bot -bt 125 604-St E-101 12340 at -50 t-t X=66 1280 = 417m 1 → dt 125 1 30.024 == 4.65 2-0020-7:00 dr 1251 10-024 128 Xo 126,29 m 2. Given distance 190mtime 4.8 Selution dolat atd. 9 (18) d. 11.320 Vat 4-84 95.49 /82 do 11.52 a do 1-52 (3.49) d. 63.631 3. Given speed 5-2mk, a=0.17an/2 distance 40.2 Solution: a speed Distance time DV 02= 5.24 + the distance traveled by bus in t time Da Vitt½ at D32 (0.179) D= 0.0895+ the distance traveled by student 5-24-0.08951+ 40.2 m 0-0845-5-24 + 40.2-0. +: 8.2 -(52)-910.0895 (46.2) 2 (0.0895) D=D₂ +40.2 t= 9.18 s cs Scanned with CamScanner Diflance trevcied by the student in time t 4. Given U: 3০০ ft s Di : ut 8.2% 0.5.29.18 D. 49.94 m b. V: Vesat C.D, VA Distance traveled by the wrudent D D40.2 m 2.01 0.08901 40.2 2.040.210 There is no solution for t so the student won't be able to caich up d. Vma 2 ad Vmn 2 (0.199ml) (0.23) Van 5.19 m/s 12119 Solution 9:45. Initial spoed UxUcox Uy Usin Acceleratio speed of any time t Vy = uy tayt: Weing-gt Dieplacement of any time Uving-51:0 H urings و "[1300) (ein 15-)]: Rucose Uwin 20 R. (200) R 2 080.25m 8. Given = 3005 020 H 30m solution: : (900 win 10")-2(9.91) (300 in 10") (9.81) h (000 cin 20) 2(9.01) 29(on) 029-81 (501596.७१) Vay 105.95 maco Y V 500 cor 10 201.9m/s (2819) (100.43) a. Given: Radius of circuler track 800 t aart Solution: arv (27) 800 total acceleration