Section 7.4 Homework and Math 6A problems
Suggestion: Do the Math 6A problems first.
Math 6A, Problem 7 on page 81
If Daniel took 2 hours to drive from Town A to Town B at 60 km/hr, then he drove a total
distance of 60 km/hr × 2 hr = 120 km. The formula, Distance = Rate × Time may be
rewritten as Time = Distance / Rate. Using this, and letting T be the time in hours for the
trip at 80 km/hr, we get
T = 120 km / (80 km/hr) = 120/80 hr = 3/2 hr = 1 hour and 30 minutes.
Math 6A, Problem 2 on page 82
a) Distance = 10 km/hr × 2 hr = 20 km.
b) His increased average speed is 12 km/hr. So the time for the trip at this speed is
20 km/(12 km/hr) = 20/12 hr = 5/3 hr = 1 hour and 40 minutes.
Section 7.4 Problems
4.
!
1.9
liter
liter
1 gal
60 sec
= 1.9
×
×
sec
sec
3.8 liter
1 min
!
1
60 liter
gal
sec
gal
= (1.9 ×
×
)
×
×
= 30
3.8
1 sec
liter
min
min
! !
! !
gal
. Note how the units cancel as if they were numbers and note also
min
!
! !
!
!
!
1 gal
60
that
is another name for 1 because 1 gallon is the same as 3.8 liters, and
3.8 liter
1
sec
is !
another name for 1 because 60 seconds is the same as 1 minute.
min
The answer is 30
!
!
!
5.
0.3 liters/ meter2 / day × 7 days/week × 6000 meter2
= (0.3 × 7 × 6000) liters/week = 12,600 liters/week
! 6. The answer is c) 48 mph.
Here is the solution: Average speed is the total distance traveld divided by the time it
took. Let D be the distance between City A and City B. And let T be the time it took to
travel from City A to City B at a speed of 60 mph. Then D/T = 60 mph.
Since T is the time it took to go from City A to City B at 60 mph, 3T/2 is the time for the
return trip at the speed of 40 mph.
The total distance for the round trip is 2D. The total time for the round trip is T + 3T/2 =
5T/2. The average speed (distance over time) is 2D/(5T/2) = 4/5 × D/T = 4/5 × 60 mph
= 48 mph.
7. Let "job" mean filling the swimming pool.
1 job
The first hose fills the pool at a rate of
.
30 hour
1 job
The second hose fills the pool at a rate of
.
70 hour
! !
1
1
job
1 job
Together they fill the pool at a rate of (
+
)
=
. So the job is
30 70 hour
21 hour
! ! is 21 hours.
completed after 21 hours. The answer
!
! ! 50 pounds
! !
8. The first corn mill grinds corn at a rate of
.
6
min
50 pounds
The second corn mill grinds corn at a rate of
.
9
min
! !
50 50 pounds 125 pounds
Together they grind corn at a rate of (
+
)
=
.
6
9
min
9
min
! !
If T is the number of minutes required to grind 1500 pounds of corn, then
!
! !
! !
125 pounds
125 pounds
× T min = 1500 pounds. So, T min = 1500 pounds ÷
=
9
min
9
min
!
!
1500 pounds ×
!
!
min
9
= 108 min. The answer is 108
! minutes.
!
125 pounds