University:
Central Michigan University
Course:
MTH 133 | Calculus II
Academic year:

2020
Views:

321

Pages:

9
Author:

Tristian Espinoza

Limits Quiz Review Name:--------------- For the function f whose graph is given, state the value of the given quantity, if it exists. Identify any discontinuities in the graph off. 1. x-3 f(x) =, (x - 3)(x -1) Domain: Range· • (- 00 IO) V ( 0 J i_ )v ( ½. ' Cl)} (.-i::io';:i )u Cl, 3)v (3 ,o0) I - - CIIO Jim f(x) limf(x) = "i X-->1- x-->3 t (3) = _un__d_e.iiV\td = 00 does not Jim f (x) = t)(1\t Jim f (x) X-->1+ f(l) = x-->1 Jim f(x) = -0 Jim f (x) X➔-oo X-->OO \' 2. Domain: Jim f(x) = 2.. Jim f(x) = 1 Jim f (x) = does not e,a:�t f(l ) = 2 X--+1- -- X➔3 --1--+--+--+---+--- 0 3. Range: [.. 2 ) 00) X X➔l Jim f(x) = 4 Jim f(x) = l X--+3- X➔3+ Jim f (x) X➔3 0 X f(3) = , = dctS not tiist = 0 o.q, t110) Jim f(x) = X--+-1 Jim f(x) = does Jim f(x) = X--+-2 x--+5 f(S) = Domain: [-2)00) V un�efit\td. no+ 4 Range: ( .. o0> 2.)v Jim f(x) = Jim f(x) = X➔O X--+-1 ex,�+ (-:z.1 ,. 4-) 3 f (-1 )= f(O) = 3 Domain: Range: (-00,-1)\J (-1, i) v ( ', 00) ( -a, -3)'1( -�,�)vO,,oo) 4. Jim f(x) = X➔-3+ t �r • • 1 i 1• r·1 . I ·1 I l . · ., , 1 •.i Jim f (x) = Jim f(x) = X➔-00 X➔2 -(I() -' Jim f(x) = Jim f(x) = Jim f(x) = dot.s riot ey.i�t X➔-3X➔OO X➔-3 oO

Math Limits Quiz Review Solution Key

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