University:
College Entrance Preparation
Course:
ACT Preparation (Mathematics)
Academic year:

2021
Views:

29

Pages:

2
Author:

puberdekgp

? UNE ’ WHAT S MY . Construct a scatter plot Draw a line of fit, then use two points on the line to find the equation of the line. ( HINT: First write your equation in point slope form , then change it to slope-intercept form.) j 2. Elevation and Temperature 1. Foot Length and Height Each of several students measured the | Temperatures were reported from various elevations on a mountain. length of his / her right foot and height. ( ) Let x = foot length cm I Let x elevation (1000’s of ft) ! y height (cm) y temperature (°F) O - I - y 159 148 126 157 138 162 180 X 24 N 22 19 23 x 20 24 28 25 17 24 26 22 161 122 155 173 146 \ : 2 160 ^ 7 2 •A _ « w 66 .-s\ ' V. 12 36 57 17 75 mS3ffi£ m i n I 5 557 7 -. .- ^ m 60 Bee eei i > j 55 50 a- 45 e3 40 35 °- 30 25 20 2 •7 = | X A 17 41 25 4 34 i \ 60 60 40 Depth (ft) two points: (kOAS ) issjiffiasgESi, , ::s I | 17 ml 1equation: y 8» 7 20 Mileage and Tread Depth Tread depth of the XL tire was measured 22 48 36 13 30 45 ' 0 - tread depth (mm) y 5.3 1.2 4.0 6.8 2.3 4.1 0.3 7.0 % fS-O £ 4.0 8- “ TS < 3.0 \ £ 2.0 : 1.0 5.7 3.3 0 1.9 ' " * 10 20 30 40 50 distance (1000’s of mi) ~ \ / H 0 13 b two points: equation:\ ~ ~~ » i ^ XT \ . PUNCHLINE •Algebra * Book A ©2006 Marcy Mathworks j \ > i * «* . - 6.0 1.9 -ffcG j J k \J Linear Equations and Their Graphs; Scatterplots and Equations for Lines of Fit 1 I for different distances driven. | Let x - distance driven (1000’s of mi) -— — —— — — —r % U o « j 4. . - 69 30 50 78 44 r~— T I Divers reported the pressure at various depths underwater Let x depth (ft) y = pressure (psi) y 50 31 41 57 39 45 20 32 42 24 52 6 7.2 55 : 8.6 : u? 50 v s 5.8 47 ' g 160 * | 45 7.5 43 150 JC 2 TO 'SI 5.1 56 | \ 40 140 8.3 39 £ k » y£ 35 130 /% 9.5 36 i 120 30 li 6.4 49 7 2 9.8 32 0 16 16 20 22 24 26 26 \ 5 6 7 6 9 10* 0 i 6.0 46 ; Foot Length (cm) Elevation (1000’s of ft) ! 9.0 40 yj ) | 5.5 49 two points:,( , two povnts:(I *6 11 l ) }1 equation: equation: N ~ 3 TVAV7 l 23 •* ••• • *•• »•»• •• *•••» •••»»•» • • *n»eee« « »»••*«*••••»•»••••••» * 3 Depth and Pressure X ot y 45 41 X 0 170 , . = = i < So * 0 *4 35- HS 30 4S 315- 330 - 35 = ^i' £ * T>S 4 < T | ( Y.~ 31s) ~T " 158° iL < x + i 1 4 3S “f 3U ><» -a it< 3-s) >5 ' o v 1 to * * * < r * VO ^r * ? @ ^350 ifics J » I ~> • -*> •i <3 84 ocx\ * : . 5 *» w 35o 3() - .i S«> 4 io WVo - ! s fco - - 1 - T5 & •- - i no < - - •H V* * i ,# * n : r U) -. . 4 i SS .. . ' . : ^ ! * H 40 ! : i ; C i 1 i J1 ^ I J * ; i : f : t I t : *- [ i >• 5 - J \ I i ! 1 J } • ; • : ; ,.i ! < ...i . . I - £$ $ * >-0-S lo,isb U % FrT* 10 m ' V T & 4 W u . ti vj Mir \<# 17 < %ci (* -&) ; S i * : I J- 4 4 •: ** ** 1 ! : ; •r i ! - *- : ••• L ! i * I : +* i : ' i — 4 f~ : .. -,• i y> 30 ' i -— - •V : 9 : : 0 : . : 1 f i i - \ fc fl o J :