University:
College Entrance Preparation
Course:
ACT Preparation (Mathematics)
Academic year:

2021
Views:

314

Pages:

3
Author:

agatoary6zt

Pg. 257 #1-15 HW #15 1. | # Sides | 7 | 8 | 9 | 10 | 11 | 20 | 55 | 100 | |---|---|---|---|---|---|---|---|---| | Sum of angle measures | 900° | 1080° | 1260° | 1440° | 1620° | 3240° | 9540° | 17640° | 2. | # Sides | 5 | 6 | 7 | 8 | 9 | 10 | 12 | 16 | 100 | | 180(n-2)/n = measure of each angle (equiangular) | 108° | 120° | 128.57° | 135° | 140° | 144° | 150° | 157.5° | 176.4° | 3. [Image of a pentagon with angles labeled] a = 122° 4. [Image of a hexagon with angles labeled] a = 116° b = 136° 5. [Image of a hexagon with angles labeled] e = 108° (see #2 above) f = 180 - 144 = 36° 6. [Image of a hexagon with angles labeled] c = 108° d = 106° 7. [Image of a hexagon with angles labeled] g = 105° h = 82° 8. [Image of a hexagon with angles labeled] j = 120° 9. [Image of a hexagon with angles labeled] k = 38° 1. What's wrong? [Image of a polygon with angles labeled] 359° should be 360° 2. What's wrong? [Image of a polygon with angles labeled] 554° should be 540° 3. See other overhead 4. Sum = 2700° # Sides = n 180(n-2) = 2700 180n - 360 = 2700 180n = 3060 n = 17 sides 5. 24 sides, 3rd century each angle = 156° (equiangular) # sides = n 180(n-2) = 156n 180n - 360 = 156n 24n = 360 n = 15 sides 6. 16-gon: 12th century each angle = 160° 180(n-2) = 160n 180n - 360 = 160n 20n = 360 n = 18 sides; 12th century 7. 20/160 360/160 = 2.25