University:
College
Course:
College Mathematics
Academic year:

2023
Views:

78

Pages:

2
Author:

Leah H.

Handout #1tan=nottan 30°=OOsin ttaneCSC Osececot e(53)cot30°53(53)OO0\00\0tan 45 :52/2(2/22)Csc45=40T!5353253302232353cot45=sec2(53)52.2CSC60 - 33(53)52T52tan 60=5345422|5252|1-2see60=1=2CSC90°-1=1tan 90 1 = 0IT53sec 90= ==060253332253323tan 180====cot 180=COS 270====II90I0IO270=2OOtan 360=180T0-1I3K2702-1O- IO3602TOIO0I2Find the Referance Angle :7K10THa) 139.4ti5)3252-180b) 252°72K>1154x- 1171,t)360-327C)327l)334R.U)-2 K2n-114-3.14180-146m)1176.28-5d) 146°4=346V)-5.8=6.98n)4T10-9.42360-3303e)-330w)10 9.42 .580)2x180-1603F)160°520P) 3R225-1804of9)225°Tq)-3t180-150h) 150°If180-150x-sor)-150i)-5 6 3State the values (NO calculator no decimals)a) sin 240°m)csc (-22-Sin 60Sin5/2(2/53)153>=270J3(53)b) tan 300°n) COS (-225°)tanco360-cosussin 606009.2T3cos 60y2.2270c) sec 1500) COS (2T) (1,0)cos 30=4(th)d) cot 2AP) sec (180)(-1,0)=-cotcost V2Cos180sin N3 53/2e) CSC11 tMCq) Cot 2T(1,0)6.2>sing12.2cos 2xsin 2A0=O-2f) cot 3TENd-cot 4/2r) CSC 3T=costillasinki42(0,-1)$212Sin 32 ==-1FAg) COS 210°cos 30-V3h) Sin 315°4s-sin 4552i) sec 225°-secusCG)n2(12)andj) tan 23%3816-tan1/2 (1/83) cos7613/2 (2/13)(53)13(F3)k) COS 8TIN23x3-cos532l) sin 11712GX+sin 44 N