University:
Dakota State University
Course:
CHEM 112 | General Chemistry I
Academic year:

2021
Views:

467

Pages:

2
Author:

lorenzops0

Stoichiometry Worksheet 3 Consider the following equation: Mg(OH)2(s) + 2 HBr(aq)  MgBr2(aq) + 2 H2O(l) 1) What type of chemical reaction is taking place? _____________________ 2) How many milliliters of 0.225 M HBr would be needed to react completely with 3.26 grams of magnesium hydroxide? 3) If 31.6 grams of magnesium hydroxide is combined with 68.0 mL of 0.725 M HBr, which is the limiting reagent? How many grams of magnesium bromide would be formed? 4) How many grams of the excess reagent will be left over after the reaction in part 3 is complete? Solutions Consider the following equation: Mg(OH)2(s) + 2 HBr(aq)  MgBr2(aq) + 2 H2O(l) 1) What type of chemical reaction is taking place? _neutralization reaction 2) How many milliliters of 0.225 M HBr would be needed to react completely with 3.26 grams of magnesium hydroxide? 3.26 g Mg(OH)2 x 1 mole Mg(OH)2 x 2 mole HBr x 1 L HBr x 1000mL HBr = 58.32 g Mg(OH)2 1 mole Mg(OH)2 0.255 mole HBr 1 L HBr = 438 mL HBr 3) If 31.6 grams of magnesium hydroxide is combined with 68.0 mL of 0.725 M HBr, which is the limiting reagent? How many grams of magnesium bromide would be formed? 31.6 g Mg(OH)2 x 1 mole Mg(OH)2 = 0.54184 mole Mg(OH)2 58.32 g Mg(OH)2 68.0 mL HBr x 1 L HBr x 0.725 mole HBr = 1000 mL HBr 1 L HBr 0.0493 mole HBr HBr is the limiting reagent. 0.0493 mole HBr x 1 mole MgBr2 x 184.11 g MgBr2 = 4.54 g MgBr2 2 mole HBr 1 mole MgBr2 4) How many grams of the excess reagent will be left over after the reaction in part 3 is complete? 0.0493 mole HBr x 1 mole Mg(OH)2 x 58.32 g Mg(OH)2 = 1.44 g Mg(OH)2 2 mole HBr 1 mole Mg(OH)2 31.6 g Mg(OH)2 - 1.44 g Mg(OH)2 = 30.2 g Mg(OH)2

Stoichiometry Worksheet 3 with Solutions

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