UNIT 4 DAY 10 HOMEWORK: QUIZ REVIEW Solve the quadratic inequalities. Write answers in interval notation. 2. x²+x-8-6 1. x ^ 2 - 11x >= - 28 x ^ 2 - 11x + 28 >= 0 Let f(x) = x ^ 2 - 11x + 28 = (x - 4)(x - 7) =0 Rightarrow x=4*27. + + f(x) 근 7 (- ∞, 4] * v[7, ∞) x ^ 2 - 4x - 7x + 28 = x(x - 4) - 7(x - 4) = 3. 6x ^ 2 + 11x - 10 > 0 Let f(x) = 6x ^ 2 + 11x - 10 = 6x ^ 2 - 4x + 15x - 10 =2x(3x-2)+5(3x2) =(3x-2)(2x+5)=0 Rightarrow x = - 5/2 * a * d * 2/3 . + z Zero + fox) (- ∞, - s/2) * v(2/3, ∞ * s) 2/3 5. Identify the transformations from the parent function f(x) = x ^ 2 g(x) = - 1/2 * (x - 8) ^ 2 + 7 Reflection abant these axis, vertical stretch by a factor of 1 Translation right & units and up 7 units x²+x-220. Let f(x) = x ^ 2 + x - 2 = x ^ 2 - x + 2x - 2 = (x-1)+2|x-1)= (x - 1)(x + 2) = 0 x= - 2nn * 2 1 + zmo + Fix) (-2,1) 4. 8x^ 2 -12<=2x^ 2 -7x Rightarrow 6x ^ 2 + 7x - 12 <= 0 Let f(x) = 6x ^ 2 + 7x - 12 =0 Rightarrow d=337. Sinje od is not a perfret square, the qualintic expression is prime over the integers. Sivie & 30, there are a distinct real solutions to the quadratic equation. + x = (- 7 plus/minus sqrt(337))/12 = (- 7 - sqrt(33))/12 = 1 - (7 + sqrt(337))/12 2m-7+4*1 7 - sqrt(317) - - 2 + sqrt(32) * [(- 7 - sqrt(317))/12, (- 7 + sqrt(33))/12] Write the equation of a quadratic function vertically stretched by a factor of 4, shifted left 3 units, and down 5 units. Y = 4 * (x + 3) ^ 2 - 5