Percent Yield Worksheet Solutions 1) Write a balanced equation for the reaction of tin (IV) phosphate with sodium carbonate to make tin (IV) carbonate and sodium phosphate. Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4 2) If 36 grams of tin (IV) phosphate is mixed with an excess of sodium carbonate, how many grams of tin (IV) carbonate will form? 36 g Sn3(PO4)4 x 1 mole Sn3(PO4)4 x 3 mole Sn(CO3)2 x 238.73 g Sn(CO3)2 = 736 g Sn3(PO4)4 1 mole Sn3(PO4)4 1 mole Sn(CO3)2 = 35 g Sn(CO3)2 3) If 29.8 grams of tin (IV) carbonate are actually formed when this reaction goes to completion, what is the percent yield? 29.8 g Sn(CO3)2 x 100 = 85% 35 g Sn(CO3)2 4) If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, how many grams of sodium phosphate will be formed? 7.3 g Na2CO3 x 1 mole Na2CO3 105.99 g Na2CO3 x 4 mole Na3PO4 x 163.94 g Na3PO4 = 6 mole Na2CO3 1 mole Na3PO4 = 7.5 g Na3PO4 theoretical (7.5 g Na3PO4) (0.74) = 5.6 g Na3PO4 actual