University:
Glendale Community College
Course:
MAT142 | College Mathematics
Academic year:

2020
Views:

270

Pages:

2
Author:

raven971nn

#1-4: Simplify (5x^2y^2)(2x^2y) = 10x^(3+2)y^(2+1) = 10x^5y^3 (7x^2y^3)(x^2y^4x^5) = 7x^(2+2+5)y^(3+4) = 7x^9y^7 (6xy)(3x^4y) = 18x^(1+4)y^(1+1) = 18x^5y^2 (x^4yz)(5x^3y^2x^5) = 5x^(4+3+5)y^(1+2)z^(1+5) = 5x^12y^3z^6 #5-8: Simplify (24x^7)/(4x^2) = 6x^(7-2) = 6x^5 (2x^2y^4)/(3x^2y) = (2/3)x^(2-2)y^(4-1) = (2/3)y^3 (16x^2y^3)/(6x^2y) = (8/3)x^(2-2)y^(3-1) = (8/3)y^2 (9x^2y^5)/(3y^4) = 3x^2y^(5-4) = 3x^2y #9-16: Simplify (5x^4)^2 = 5^2x^(4*2) = 25x^8 (6x)^3 = 6^3x^3 = 216x^3 (2x^2y)^3 = 2^3x^(2*3)y^3 = 8x^6y^3 (5xy)^2 = 5^2x^2y^2 = 25x^2y^2 (5xy^2)^3(7x^4y) = 125x^(3+4)y^(6+1) = 875x^7y^7 (2xy^4)(xy^5)^2 = 2x^(1+2)y^(4+10) = 2x^3y^14 (x^2y^3)(xy^4)^5 = x^(2+5)y^(3+20) = x^7y^23 (3xy^2)^2(2x^2y)^4 = 9x^(2+8)y^(4+4) = 144x^10y^8 #17-20: Simplify the expression (-8)^1 = -8 (-8)^0 = 1 (16y)^1 = 16y (16y)^0 = 1 #21-28: Simplify the expression. Write the answer with positive exponents only. 4x^3 (12x)/(2ax^2) = (6)/(ax^(2-1)) = (6)/(ax) (3x^2y^4)/(2x^2y) = (3/2)y^(4-1) = (3/2)y^3 (9x^3y^4)/(3x^2y^2) = 3x^(3-2)y^(4-2) = 3xy^2 (12x^2y^5)/(4x^2y^2) = 3y^(5-2) = 3y^3 (8x^3y^4)/(2x^2y) = 4x^(3-2)y^(4-1) = 4xy^3 (16x^2y^5)/(4x^2y^3) = 4y^(5-3) = 4y^2 (24x^3y^4)/(6x^2y^2) = 4x^(3-2)y^(4-2) = 4xy^2 #23-28: Simplify [\frac{12x^{2}y^{4}}{2x^{2}y^{3}}=\frac{6}{x^{4-1}y^{7-3}}=\boxed{\frac{6}{x^{3}y^{4}}}] [\frac{12x^{2}y^{4}}{nxy^{4}}=\frac{3y^{6-5}}{2}=\boxed{\frac{3y}{2}oR\frac{3}{2}y}] ((\frac{4}{x^{2}})^{-2}=(\frac{x^{4}}{4})^{2}=\frac{x^{8}}{4^{2}}=\boxed{\frac{x^{8}}{16}}) ((\frac{1}{2})^{-3}=(\frac{2}{3})^{3}=\frac{2^{3}}{3^{3}}=\boxed{\frac{8}{22}}) [\frac{x^{2}}{x^{3}}=\frac{1}{x^{5-2}}=\boxed{\frac{1}{x^{3}}}] (\frac{x^{\prime}}{x^{7}}=x^{5-2}=\boxed{x^{3}}) #29-35: Divide [\frac{32x^{3}y^{3}-16x^{2}y^{3}+axy}{4xy}] ((15y^{3}-6y^{2}+12y)\div(2y)) ((7x^{2}+6x+3)\overline{+(}x)) ((2x^{2}-7x-10)\div(2x+3)) ((3x^{2}+19x+20)\div(x+5)) ((x^{2}+11x+5)\div(x+1)) ((3x^{2}+8x+5)\div(3x+5)) Answers: (10x^{5}\gamma^{3}) (7x^{0}y^{5}2^{11}) (18x^{5}y^{2}) (5x^{7}y^{3}z^{6}) (4x^{2}) (\frac{3x^{9}}{-2}) (3x^{3}y^{2}) [\frac{ay^{*}}{3}] (25x^{0}) (216x^{9}) (8x^{15}y^{3}) [25x^{6}y^{2}] (875x^{7}y^{7}) (2x^{2}y^{10}) [x^{7}y^{21}] [144x^{10}y^{2}] -1 1 16 1 (\frac{4}{x^{3}}) [\frac{3}{5x}] (\frac{6}{x^{3}y^{*}}) [\frac{3y}{2}oR\frac{3}{2}y] [\frac{\pi^{8}}{16}] [\frac{8}{22}] (\frac{1}{x^{2}}) (x^{3}) (8x^{2}y^{2}-4xy^{2}+2) (\frac{15y^{2}}{2}-3y+6) or (y²-6) (7x+6+\frac{3}{x}) x-5 RS (3x+4) x+10 R (-5) (x+1)