University:
High School
Course:
High School Algebra
Academic year:

2020
Views:

385

Pages:

1
Author:

hundeshowgv

Solving exponential & Logarithmic Equations (Part 2) . . _ -=-q u_ aь_·on_ s_ ___ _ n-=-g _the 1-T_ar_ g.;;_e t_ 6В_W_e ar_ e_ I_ eam_i _ p ..;:.. ro _ p_ ---1 -=- em_· e_s_o_f _lo-=-gan_ th_m_s_so_ th _ _ at_ w_e_c_ an_ s_o_Ive_ l_ o....::g_ar _ithm_1_· c e So lve, roun d to the n earest ten th. 3. з n/2 = 7 1. z x = 7 2. 15 2k + 2.4 = 80 How do we solve if we n 2 cannot make the numbers I 3 -1- :: 1091'7 IQ J Г) '/. � о оп both sides the same ...,,�.,,..�-Ч -;;t,Ч 9 r;J.., J 15 :: 77,� l(l+'l.)·I03ЗiD9\'7 base? 1 о� ? \Oj �1\ J v n-t2 =- � -z. 0 Use the def"шition of а / Q_ 11 2 _ �� 7 logarithm: � "Х.103 JS ;;.1091'5 f< ;11oq/S � logь у = х +-+ ь х = у Eva1Jat� usin 1л с angc ofbasc formula. RoW1d to tl1e ncarcsYtentl1. 4. log3 15 5. log6 10 6. log5 125 То evaluate any logarithm using а calcualtor, use tbe �_!_О_Э_l0 change of base formula: оа 1 7 l�o � • \ 09 ��J_Q_g_l ifi 18 -�-= logca We сап also use the log properties to solve exponential equations and equations involving logs. Product Property Iogь т + Iogь п = Iogь тп Quotient Property Iogь т п = п Iogь т ;;. So]ve, round to the nearest tenth. 7. log2 4 + log2 (x - 1) = 3 1092 4 ( Х-1 ) == 3 -....___-,, ��7-1+()(-1) �=у J-4 �ч +Ч -�� 113-S 9. log 5 + log (2x + 3) = 2 4 Power Property JK•1oз1s�1og77_lo= ::l097?_�: \ ьэ (о �[}] Ioga = -1 ogc 4 1ь9�==2 12-:, Б[ 2-Х-+-З) 1to�1ox +\S -,s 15 1-=- IO� О - Т Summary: Today I leamed Th is con n ects to wh at I know about Wh at I leamedtoda can hel m e l ater when J_ -Х 11\) з Joo. 71. � :: _LОЗЕ� /О 9� ,00 �о·