University:
High School
Course:
High School Geometry
Academic year:

2019
Views:

153

Pages:

2
Author:

plagiinduh1

Right Triangle Trigonometry - Day 2 In Exercises 5 and 6, find the value of x for the right triangle. 5. Diagram: A right triangle with a 30° angle. The hypotenuse is labeled as 16, the adjacent side is labeled as "w", and the opposite side is labeled as "x". Solution: cos(30°) = adj/hyp cos(30°) = w/16 16 * cos(30°) = x x = 16 * cos(30°) x = 8√3 (exact form) 6. Diagram: A right triangle with a 45° angle. The hypotenuse is labeled as 20, the adjacent side is labeled as "w", and the opposite side is labeled as "x". Solution: x = w√2 20 = w√2 20/√2 = w w = 10√2 x = w√2 x = 10√2 * √2 x = 20 7. Diagram: A right triangle with a 60° angle. The hypotenuse is labeled as 11, the adjacent side is labeled as "w", and the opposite side is labeled as "x". Solution: w = x/√3 11 = 2w 11/2 = w x = w√3 x = (11/2)√3 x = 5.5√3 or 11√3/2 8. A parasailor is attached to a boat with a rope 80 feet long. The angle of elevation from the boat to the parasailor is 36°. Estimate the parasailor's height above the boat. Round your answer to the nearest tenth. Diagram: A right triangle is drawn. The hypotenuse represents the 80-foot rope. The angle of elevation (36°) is labeled at the base of the triangle. The height of the parasailor is labeled as "x" (opposite side). Calculations: sin(36°) = x / 80 80 * sin(36°) = x 80 * (0.5878) = x 47.02 = x 47 feet ≈ x