Continuation - Edubirdie

University:
Massachusetts Institute of Technology
Course:
18.01 | Single Variable Calculus
Academic year:

2020
Views:

411

Pages:

1
Author:

Nathanael Mcmahon

Lecture 7 Sept. 21, 2006 18.01 Fall 2006 Lecture 7: Continuation Hyperbolic Sine and Cosine Hyperbolic sine (pronounced “sinsh”): sinh(x) = ex − e−x 2 Hyperbolic cosine (pronounced “cosh”): ex + e−x 2 � x � d d e − e−x ex − (−e−x ) sinh(x) = = = cosh(x) dx dx 2 2 cosh(x) = Likewise, d cosh(x) = sinh(x) dx d cos(x).) dx (Note that this is diﬀerent from Important identity: cosh2 (x) − sinh2 (x) = 1 Proof: �2 � x �2 ex + e−x e − e−x − 2 2 � 1 � 2x � 1 � 2x 1 e + 2ex e−x + e−2x − e − 2 + e−2x = (2 + 2) = 1 4 4 4 � cosh2 (x) − sinh2 (x) = cosh2 (x) − sinh2 (x) = Why are these functions called “hyperbolic”? Let u = cosh(x) and v = sinh(x), then u2 − v 2 = 1 which is the equation of a hyperbola. Regular trig functions are “circular” functions. If u = cos(x) and v = sin(x), then u2 + v 2 = 1 which is the equation of a circle. 1

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