Surface Area of a Sphere In this example we will complete the calculation of the area of a surface of rotation. If we’re going to go to the eﬀort to complete the integral, the answer should be a nice one; one we can remember. It turns out that calculating the surface area of a sphere gives us just such an answer. We’ll think of our sphere as a surface of revolution formed by revolving a half circle of radius a about the x-axis. We’ll be integrating with respect to x, and we’ll let the bounds on our integral be x1 and x2 with −a ≤ x1 ≤ x2 ≤ a as sketched in Figure 1. x1 x2 Figure 1: Part of the surface of a sphere. Remember that in an earlier example we computed the length of an inﬁnites imal segment of a circular arc of radius 1: � 1 ds = dx 1 − x2 In this example we let the radius equal a so that we can see how the surface area depends on the radius. Hence: � y = a2 − x2 −x y� = √ a 2 − x2 � x2 ds = 1+ 2 dx a − x2 � a2 − x2 + x2 = dx a2 − x2 � a2 = dx. a2 − x2 The formula for the surface area indicated in Figure 1 is: � x2 Area = 2πy ds x1 1 y � � �� x2 � 2π a2 − x2 ds �� a2 = dx a2 − x2 x � x1 2 � a = 2π a2 − x2 √ dx 2 a − x2 x � x1 2 = 2πa dx � x1 = 2πa(x2 − x1 ). Special Cases When possible, we should test our results by plugging in values to see if our answer is reasonable. Here, if we set x1 = 0 and x2 = a we should get the surface area of a hemisphere of radius a: Figure 2: Right hemisphere. 2πa(x2 − x1 ) = = 2πa(a − 0) 2πa2 We get the surface area of the whole sphere by letting x1 = −a and x2 = a: 2πa(x2 − x1 ) = 2πa(a − (−a)) = 4πa2 Question: Would it be possible to rotate around the y-axis? Answer: Yes. If we rotate around the y axis and integrate with respect to x (calculating the surface area of a vertical slice, as we did here) we’d be 2 adding up little strips of area. If we integrate with respect to y and ﬁnd the surface area between two vertical positions y1 and y2 we’d get exactly the same calculation. Question: Can you compute surface area using shells? Answer: The short answer is “not quite”. We use the word shell to describe something which has a thickness dx. Shells have volume, integrals which involve shells compute volumes, not surface areas. To compute surface area you need to sum up the areas of small regions of your surface, but those small regions can have any shape whose area you can measure. 3