Hyperbolic Angle Sum Formula Find sinh(x + y) and cosh(x + y) in terms of sinh x, cosh x, sinh y and cosh y. Solution sinh(x + y) Recall that: eu − e−u eu + e−u and cosh(u) = . 2 2 The easiest way to approach this problem might be to guess that the hyper bolic trig. angle sum formulas will be similar to those from regular trigonometry, then adjust those formulas to ﬁt. To proceed without consulting the angle sum formulas, we start by rewriting sinh(x + y) in terms of ex and ey and then attempt to separate the terms. A ﬁrst attempt might look like: sinh(u) = sinh(x + y) = = = ex+y − e−x−y 2 1 x+y (e − e−x−y ) 2 1 x+y (e − e−x−y + ey−x − ex−y − ey−x + ex−y ) 2 Using the fact that: (ea + e−a )(eb − e−b ) = ea+b + eb−a − ea−b + e−a−b we could write sinh(x + y) as 2 cosh x sinh y plus some left over stuﬀ. However, we would then have to do something with the left over stuﬀ, and the coeﬃcient of 2 on 2 cosh x sinh y seems out of place. Let’s try again: sinh(x + y) = = = = = = sinh(x + y) = ex+y − e−x−y 2 1 x+y (2e − 2e−x−y ) 4 1 x+y (e − e−x−y + ey−x − ex−y + ex+y − e−x−y − ey−x + ex−y ) 4 1 x+y 1 (e − e−x−y + ey−x − ex−y ) + (ex+y − e−x−y − ey−x + ex−y ) 4 4 1 x 1 x −x y −y −x (e + e )(e − e ) + (e − e )(ey + e−y ) 4 4 ex + e−x ey − e−y ex − e−x ey + e−y + 2 2 2 2 cosh x sinh y + sinh x cosh y We know that sin(x + y) = sin x cos y + cos x sin y, so this seems like a reasonable answer. It’s a straightforward exercise to check this result using our formulas for sinh u and cosh u. 1 cosh(x + y) We proceed as before, without the false start. cosh(x + y) = = = = = cosh(x + y) = ex+y + e−x−y 2 1 x+y (e + e−x−y ) 2 1 x+y (e + e−x−y + ey−x + ex−y + ex+y + e−x−y − ey−x − ex−y ) 4 1 x+y 1 (e + e−x−y + ey−x + ex−y ) + (ex+y + e−x−y − ey−x − ex−y ) 4 4 1 x 1 (e + e−x )(ey + e−y ) + (ex − e−x )(ey − e−y ) 4 4 cosh x cosh y + sinh x sinh y We know that cos(x + y) = cos x cos y − sin x sin y, so again this is a plausible result. 2