Ch.1 Problem 1.35 Solution | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

200

Pages:

1
Author:

esfredint7qo

PROBLEM 1.35 A 1060-kN load P is applied to the granite block shown. Determine the resulting maximum value of (a) the normal stress, (b) the shearing stress. Specify the orientation of the plane on which each of these maximum values occurs. SOLUTION A0 = (140 mm)(140 mm) = 19.6 × 103 mm 2 = 19.6 × 10−3 m 2 P = 1060 × 10 3 N σ = (a) P 1060 × 103 cos 2 θ = cos 2 θ = 54.082 × 10 6 cos 2 θ A0 19.6 × 10−3 Maximum tensile stress = 0 at θ = 90°. Maximum compressive stress = 54.1 × 106 at θ = 0°. (b) |σ |max = 54.1 MPa W Maximum shearing stress: τ max = P 1060 × 10 3 = = 27.0 ×10 6 Pa at θ = 45 °. A 2 0 (2)(19.6 ×10 − 3) τmax = 27.0 MPa W

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