Ch.1 Problem 1.10 Solution | Study Guide - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
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107

Pages:

1
Author:

folclord7m

PROBLEM 1.10 Three forces, each of magnitude P = 4 kN, are applied to the mechanism shown. Determine the cross-sectional area of the uniform portion of rod BE for which the normal stress in that portion is +100 MPa. SOLUTION Draw free body diagrams of AC and CD. Free Body CD: Σ M D = 0: 0.150 P − 0.250C = 0 C = 0.6 P Free Body AC: Required area of BE: M A = 0: 0.150 FBE − 0.350 P − 0.450 P − 0.450 C = 0 FBE = 1.07 P = 7.1333 P = (7.133)(4 kN) = 28.533 kN 0.150 σ BE = FBE ABE ABE = FBE σ BE = 28.533 × 103 − = 285.33 × 10 6 m 2 100 × 10 6 ABE = 285 mm2 W

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