Ch.1 Problem 1.38 Solution - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

409

Pages:

1
Author:

do3ran7ut

PROBLEM 1.38 Link BC is 6 mm thick and is made of a steel with a 450-MPa ultimate strength in tension. What should be its width w if the structure shown is being designed to support a 20-kN load P with a factor of safety of 3? SOLUTION Use bar ACD as a free body and note that member BC is a two-force member. ΣM A = 0: (480)F BC − 600 P = 0 FBC = 600P (600)(20 × 10 3) = = 25 × 10 3N 480 480 For a factor of safety F.S. = 3, the ultimate load of member BC is FU = (F.S.)( FBC ) = (3)(25 × 10 3) = 75 × 10 3N But FU = σU A ∴A = For a rectangular section FU σU = 75 × 103 = 166.67 × 10− 6 m 2 450 × 10 6 A = wt or w = A 166.67 × 10 −6 = t 0.006 w = 27.8 × 10− 3m or 27.8 mm W

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