Ch.1 Problem 1.60 Solution | Study Guide - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
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495

Pages:

1
Author:

ilikemyicons0y5

PROBLEM 1.60 Two horizontal 5-kip forces are applied to pin B of the assembly shown. Knowing that a pin of 0.8-in. diameter is used at each connection, determine the maximum value of the average normal stress (a) in link AB, (b) in link BC. SOLUTION Use joint B as free body. Law of Sines FAB F 10 = BC = sin 45° sin 60° sin 95° F AB = 7.3205 kips FBC = 8.9658 kips Link AB is a tension member. Minimum section at pin. Anet = (1.8 − 0.8)(0.5) = 0.5 in 2 (a) Stress in AB : σ AB = F AB 7.3205 = A net 0.5 σ AB = 14.64 ksi W Link BC is a compression member. Cross sectional area is A = (1.8)(0.5) = 0.9 in 2 (b) Stress in BC: σ BC = −F BC −8.9658 = 0.9 A σ BC = −9.96 ksi W

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