Ch.1 Problem 1.14 Solution | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

132

Pages:

1
Author:

Alexa Livingston

PROBLEM 1.14 A couple M of magnitude 1500 N ⋅ m is applied to the crank of an engine. For the position shown, determine (a) the force P required to hold the engine system in equilibrium, (b) the average normal stress in the connecting rod BC, which has a 450-mm2 uniform cross section. SOLUTION Use piston, rod, and crank together as free body. Add wall reaction H and bearing reactions Ax and Ay. Σ M A = 0 : (0.280 m) H − 1500 N ⋅ m = 0 H = 5.3571 × 10 3N Use piston alone as free body. Note that rod is a two-force member; hence the direction of force FBC is known. Draw the force triangle and solve for P and FBE by proportions. l= 2002 + 602 = 208.81 mm P 200 = H 60  ∴ P = 17.86 × 10 3N (a) P = 17.86 kN W FBC 208.81 = ∴ FBC = 18.643 × 10 3 N H 60 Rod BC is a compression member. Its area is 450 mm 2 = 450 × 10 − 6m 2 Stress, σ BC = − FBC −18.643 × 103 = = −41.4 × 10 6 Pa A 450 × 10 −6  (b) σ BC = −41.4 MPa W

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