Ch.1 Problem 1.63 Solution | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

409

Pages:

1
Author:

Maverick Martin

PROBLEM 1.63 Two wooden planks, each 21 in. thick and 9 in. wide, are joined by the dry mortise joint shown. Knowing that the wood used shears off along its grain when the average shearing stress reaches 1.20 ksi, determine the magnitude P of the axial load that will cause the joint to fail. SOLUTION Six areas must be sheared off when the joint fails. Each of these areas has dimensions being A= 5 8 in. × 1 2 in., its area 5 1 5 2 in = 0.3125 in 2 × = 8 2 16 At failure, the force carried by each area is F = τ A = (1.20 ksi)(0.3125 in 2 ) = 0.375 kips Since there are six failure areas, P = 6 F = (6)(0.375) P = 2.25 kips W

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