University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

210

Pages:

1
Author:

sonalhava9qv

PROBLEM 1.49 5 A steel plate 16 in. thick is embedded in a horizontal concrete slab and is used to anchor a high-strength vertical cable as shown. The diameter of the hole in the plate is 34 in., the ultimate strength of the steel used is 36 ksi, and the ultimate bonding stress between plate and concrete is 300 psi. Knowing that a factor of safety of 3.60 is desired when P = 2.5 kips, determine (a) the required width a of the plate, (b) the minimum depth b to which a plate of that width should be embedded in the concrete slab. (Neglect the normal stresses between the concrete and the lower end of the plate.) SOLUTION Based on tension in plate: A = (a − d )t PU = σ U A F. S. = PU σ U (a − d )t = P P Solving for a, a =d + ( F.S.) P 3 (3.60)(2.5) = + 4 σU t (36) 165 ( ) (a) a = 1.550 in. W Based on shear between plate and concrete slab, τ U = 0.300 ksi A = perimeter × depth = 2(a + t )b PU = τ U A = 2τ U (a + t )b Solving for b, b= F .S . = PU P ( F. S.) P (3.6)(2.5) = 5 (0.300) 2( a + t)τ U (2) 1.550 + 16 ( ) (b) b = 8.05 in. W