Ch.1 Problem 1.32 Solution | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 100 | Introduction to Engineering Design
Academic year:

2021
Views:

429

Pages:

1
Author:

Leilani Contreras

PROBLEM 1.32 Two wooden members of uniform rectangular cross section are joined by the simple glued scarf splice shown. Knowing that the maximum allowable shearing stress in the glued splice is 620 kPa, determine (a) the largest load P that can be safely applied, (b) the corresponding tensile stress in the splice. SOLUTION θ = 90 ° − 45 ° = 45 ° A0 = (150)(75) = 11.25 × 103 mm2 = 11.25 × 10−3 m2 τ = 620 kPa = 620 × 10 3Pa P sin 2θ τ= 2 A0 (a) P= −3 2 A0τ (2)(11.25 × 10 )(620 × 10 3) = sin2θ sin 90° = 13.95 × 10 3N (b) σ = P = 13.95 kN W P cos θ (13.95 × 10 )(cos 45°) = A0 11.25 × 10−3 2 = 620 × 10 3Pa 3 2 σ = 620 kPa W

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