COSMOS Chapter 4 Solution 144 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

157

Pages:

2
Author:

Kundulu8mbj

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 144. Free-Body Diagram: Express forces in terms of their rectangular components: uuur − 40 i + 74 j − 32 k BG 37 16   20 = TBG = TBG  − i + TBG = TBG j− k 2 2 2 BG 45 45 45   − + + − 40 74 32 ( ) ( ) ( ) TBH = TBH uuuur BH = TBH BH 30 i + 60 j − 60 k ( 30 )2 + ( 60 )2 + ( − 60 )2 2 2  1 = TBH  i + j − k  3 3  3 P = − ( 75 lb ) j λ AD uuur AD = = AD 80 i − 60 j 2 (80 ) + ( − 60 ) 2 = 0.8 i − 0.6 j continued COSMOS: Complete Online Solutions Manual Organization System rB/A = ( 40 in.) i rC/A = ( 80 in.) i Now, ΣM AD = 0: ( ) ( ) ( ) λ AD ⋅ rB/ A × TBG + λ AD ⋅ rB/ A × TBH + λ AD ⋅ rC/ A × P = 0 0.8 0 − 0.6 0.8 0 − 0.6 0.8 0 − 0.6 TBG TBH + 40 0 0 + 80 0 40 0 0 0 =0 45 3 − 20 37 −16 1 2 2 0 − 75 0 − 888 48 TBG − TBH + 3600 = 0 45 3 Noting that TBG = TBH = T and solving: T = 100.746 lb or T = 100.7 lb

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