COSMOS Chapter 6 Solution 156 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

137

Pages:

2
Author:

Arielle Armstrong

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 156. FBD Truss: ΣM E = 0: ( 9 ft ) Fy − ( 6.75 ft )( 4 kips ) − (13.5 ft )( 4 kips ) = 0 Fy = 9 kips ΣFy = 0: − E y + 9 kips = 0 E y = 9 kips ΣFx = 0: − Ex + 4 kips + 4 kips = 0 E x = 8 kips By inspection of joint E: FEF = 8.00 kips T ! Joint FBDs: Joint F: FEC = 9.00 kips T ! By inspection of joint B: FAB = 0 ! FBD = 0 ! ΣFx = 0: Joint C: 4 FCF − 8 kips = 0 5 ΣFy = 0: FDF − 3 (10 kips) = 0 5 ΣFx = 0: 4 kips − FCF = 10.00 kips C ! FDF = 6.00 kips T ! 4 (10 kips ) + FCD = 0 5 FCD = 4.00 kips T ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. COSMOS: Complete Online Solutions Manual Organization System ΣFy = 0: FAC − 9 kips + 3 (10 kips ) = 0 5 FAC = 3.00 kips T ! Joint A: ΣFx = 0: 4 kips − 4 FAD = 0 5 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. FAD = 5.00 kips C !

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