COSMOS Chapter 8 Solution 105 - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2021
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 105. Horizontal pipe: Contact angles β H = Vertical pipe π Contact angle βV = π 2 µ sH = 0.25 µ sV = 0.2 For P to impend downward, ( ) ( ) µ π µ π µ π µ π P =  e sH 2  Q =  e sH 2  e µsV π R =  e sH 2  e µsV π  e sH 2  (100 lb )         π µ +µ Pmax = e ( sH sV )  (100 lb ) = (100 lb ) e0.45π = 411.12 lb   For 100 lb to impend downward, the ratios are reversed, so 100 lb = Pe0.45π , Pmin = 24.324 lb So, for equilibrium, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. 24.3 lb ≤ P ≤ 411 lb

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