COSMOS Chapter 6 Solution 150 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
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375

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 150. FBD Bucket (one side): (a) ΣM D = 0: ( 0.8 m ) ( 2.4525 kN ) − ( 0.5 m ) FAB = 0 FAB = 3.924 kN w = ( 250 kg ) ( 9.81 N/kg ) = 2452.5 N = 2.4525 kN FBD link BE: ΣM E = 0: ( 0.68 m )( 3.924 kN ) − ( 0.54 m )  80  FCD   89   39  + ( 0.35 m )  FCD  = 0,  89  FCD = 7.682 kN FCD = 7.68 kN C W FBD top blad (b) FBD Entire linkage: ΣM G = 0: ( 2.5 m ) ( 2.4525 kN ) 1 1 FGH − ( 0.6 m ) FGH = 0, 2 2 FFH = 21.677 kN, FFH = 21.7 kN C W + ( 0.2 m ) Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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