COSMOS Chapter 9 Solution 109 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

55

Pages:

1
Author:

Lamghari6kx

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 109. First assume Ix > I y ( )max is (Note: Assuming I x < I y is not consistent with the requirement that the axis corresponding to the I xy obtained by rotating the x axis through 67.5° counterclockwise) 2θ m = 2 ( 67.5° ) − 90° = 45° From Mohr’s circle have (a) tan 2θ m = From Have I x = I y + 2 I xy tan 2θ m = 300 in 4 + 2 2 I xy Ix − I y 125 in 4 = 550 in 4 tan 45° or I x = 550 in 4 (b) Now and Then I ave = R= 1 550 + 300 4 Ix + I y = in = 425 in 4 2 2 ( I xy sin 2θ m ) = 125 in 4 = 176.78 in 4 sin 45° I max, min = I ave ± R = ( 425 ± 176.76 ) in 4 = ( 601.78, 248.22 ) in 4 or I max = 602 in 4 and I min = 248 in 4

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