COSMOS Chapter 9 Solution 159 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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438

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1
Author:

MoGhoadoAnotozj11

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 159. Have m= wL g Then m1 = w 3  π × a  g 2  = 3π wa 2 g m2 = w ( 2a ) g =2 m3 = w (π × a ) g =π wa g I uv = I u′v′ + mu v Now I x′y′ = I y′z ′ = I z ′x′ = 0 Symmetry implies ∴ Then wa g for each element. Iuv = ∑ miui v i  3π wa   3  2 3   wa  2  I xy =    a  × a  +  π  ( 3a )  × a  π   2 g   2  π 2   g  3 wa  27  = + 6  g  4  I xy = 12.75 w 3 a g I yz = 7 wa3 g  3π wa   2 3   wa   2 × a  I yz =    × a  ( 2a ) +  π  (− a)  2 g  π 2   g  π  = wa3 (9 − 2) g  3π wa   wa   3   wa  I zx =   ( 2a )  a  +  2  ( a )( 3a ) +  π  ( − a )( 3a ) 2   g   2 g   g  = wa3  9π  + 6 − 3π   g  2  I zx = 1.5 w 3 a (π + 4 ) g

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