University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
Views:

283

Pages:

1
Author:

Lamghari6kx

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 60. Free-Body Diagram: Spring force: Fs = ks = k ( l − l cosθ ) = kl (1 − cosθ ) (a) l  Fs ( l sin θ ) − W  cosθ  = 0 2  ΣM D = 0: kl (sin θ − cosθ sin θ ) − kl (tan θ − sin θ ) − (b) W cosθ = 0 2 W =0 2 or tan θ − sin θ = W 2kl For given values of W = 4 lb, l = 30 in., k = 1.8 lb/ft = 0.15 lb/in. tan θ − sin θ = Solving numerically: 4 lb = 0.44444 2(0.15 lb/in.)(30 in.) θ = 50.584° or θ = 50.6°