COSMOS Chapter 3 Solution 39 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

118

Pages:

1
Author:

Nicole Wang

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 39. (a) By definition λ BC + λ EF = (1) (1) cosθ where λ BC = = λ EF = = Therefore ( 32 ft ) i − ( 9 ft ) j − ( 24 ft ) k ( 32 )2 + ( − 9 )2 + ( − 24 )2 ft 1 ( 32i − 9 j − 24k ) 41 − (14 ft ) i − (12 ft ) j + (12 ft ) k ( −14 )2 + ( −12 )2 + ( 12 )2 ft 1 ( −7i − 6 j + 6k ) 11 ( 32i − 9 j − 24k ) ⋅ ( −7i − 6 j + 6k ) 41 11 = cosθ ( 32 )( −7 ) + ( −9 )( −6 ) + ( −24 )( 6 ) = ( 41)(11) cosθ cosθ = − 0.69623 or (b) By definition (TEG ) BC θ = 134.1° W = (TEF ) cosθ = (110 lb )( −0.69623) = −76.585 lb or (TEF ) BC = −76.6 lb W .

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