COSMOS Chapter 8 Solution 4 | Michigan State University - Edubirdie

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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2021
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 4. Tension in cord is equal to P = 62.5 N, from FBD of pulley. ( ) W = (10 kg ) 9.81 m/s 2 = 98.1 N ΣFy = 0: N − ( 98.1 N ) cos 20° + ( 62.5 N ) sin15° = 0 N = 76.008 N Fmax = µ s N = ( 0.30 )( 76.008 N ) = 22.802 N For equilibrium: ΣFx = 0: ( 62.5 N ) cos15° − ( 98.1 N ) sin 20° − F = 0 Feq = 26.818 N > Fmax so no equilibrium, and block slides up the incline Fslip = µ x N = ( 0.25 )( 76.008 N ) = 19.00 N F = 19.00 N Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. 20°

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