COSMOS Chapter 4 Solution 68 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
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401

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 68. Free-Body Diagram: Let C be the intersection of the lines of action of the three forces acting on the girder From triangle BCD: h = ( 40 ft ) cot 30° = 69.282 ft From triangle ACD:  69.282 ft   = 73.8979°  20 ft  α = tan −1  or α = 73.9° From force triangle: β = 90° − α = 90° − 73.8979° = 16.1021° γ = 180° − 30° − β = 180° − 30° − 16.1021° = 133.898° Using the law of sines: TA TB 6000 lb = = sin 30° sin16.1021° sin133.898° Solving for TA and TB : TA = 4163.3 lb, TB = 2309.4 lb or TA = 4160 lb and TB = 2310 lb

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