COSMOS Chapter 6 Solution 142 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2020
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359

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1
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Lamghari6kx

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 142. FBD CD: θ = tan − 1 ΣM D = 0: 0.85 in. − 0.3 in. = 22.932° 2.6 in. − 1.3 in. ( 3.4 in.)( 30 lb ) − ( 0.8 in.) FAC sin 22.932° + ( 0.3 in.) FAC cos 22.932° = 0 FAC = 2879.6 lb ΣFx = 0: Dx − ( 2879.6 lb ) cos 22.932° = 0, Dx = 2652.0 lb ΣFy = 0: Dy − ( 2879.6 lb ) sin 22.932° + 30 lb = 0, Dy = 1092.00 lb FBD BD: ΣM B = 0: ( 2.6 in.) F + ( 0.2 in.)(1092.00 lb ) − ( 0.85 in.)( 2652.0 lb ) = 0 F = 783 lb W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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