COSMOS Chapter 3 Solution 65 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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74

Pages:

1
Author:

omiliar74be

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 65. From the solution of Problem 3.60: λ DI = 0.97014 i − 0.24254 j TEG = ( 2.4 lb ) i − ( 7.2 lb ) j − ( 23.4 lb ) k TEG = 24.6 lb M DI = − 224.74 lb ⋅ ft Only the perpendicular component of TEG contributes to the moment of TEG about line DI. The parallel component of TEG will be used to find the perpendicular component. Have ( TEG )Parallel = λ DI ⋅ TEG = [ 0.97014 i − 0.24254 j] ⋅ ( 2.4 lb ) i − ( 7.2 lb ) j − ( 23.4 lb ) k  = ( 2.3283 + 1.74629 ) = 4.0746 lb Since TEG = ( TEG )Perpendicular + (TEG )Parallel Then (TEG )Perpendicular = (TEG )2 − (TEG )2Parallel = ( 24.6 )2 − ( 4.0746 )2 = 24.260 lb and M DI = (TEG )Perpendicular d 224.74 lb ⋅ ft = ( 24.260 lb ) d d = 9.2638 ft or d = 9.26 ft .

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