COSMOS Chapter 9 Solution 7 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

251

Pages:

1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 7. At x = 0: 0 = k ( b + c ) First note: or 2 c = −b At x = a : a = k ( 2b − b ) Have or k = a b2 ∴ x= a 2 y − b) 2( b 2 I x = ∫ y 2dA =∫ a 2 y − b) 2b b 2 ( b 0 ∫ y 2dxdy = a 2b 2 2 y ( y − b ) dy 2 ∫b b = a 2b 4 y − 2by 3 + b 2 y 2 dy 2 ∫b b = a 1 5 1 4 1 2 3  y − by + b y  2 3 b2  5 b = a  1 1 1 2 1 2 3  5 4 3 1 5 1 4  ( 2b ) − ( 2b ) + b ( 2b )  −  b − b b + b b   2 3 5 2 3 b 2   5    ( ) 2b ( ) ( ) 8 1 1 1  32 = ab3  −8+ − + −  3 5 2 3  5 = 31 3 ab 30 Ix = 31 3 ab 30

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