COSMOS Chapter 9 Solution 191 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
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302

Pages:

1
Author:

diamundgalx45p

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 191. y , mm yA, mm3 50.9296 1.1520 × 106 30 − 0.324 × 106 A, mm 2 π 1 2 Σ Now 2 − (120 )2 = 22 619.5 1 ( 240 )( 90 ) = −10 800 2 11 819.5 Y = 0.828 × 106 ΣAY 0.828 × 106 mm3 = = 70.054 mm ΣA 11819.5 mm 2 J O = ( J O )1 − ( J O )2 (a) where and ( J O )1 = π 4 (120 mm ) = 162.86 × 10 ( J O ) 2 = ( I x′ ) 2 + ( I y ′ ) 2 4 = 6 mm 4 1 1 ( 240 mm )( 90 mm )3 + 2  ( 90 mm )(120 mm )3  12 12  = 40.5 × 106 mm 4 Then J O = (162.86 − 40.5 ) × 106 mm 4 = 122.36 × 106 mm 4 or J O = 122.4 × 106 mm 4 ! J O = J C + Ay 2 (b) or ( ) J C = 122.36 × 106 mm 4 − 11 819.5 mm 2 ( 70.054 mm ) 2 = (122.36 − 58.005 )106 mm 4 or J C = 64.4 × 106 mm 4 !

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