COSMOS Chapter 6 Solution 162 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2021
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439

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1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 162. FBD Frame: ΣM F = 0: (10.8 ft ) Ay − (12 ft )( 4.5 kips ) = 0 A y = 5.00 kips ΣFx = 0: W − Ax + 4.5 kips = 0 A x = 4.50 kips FBD member ABC: W Note: BE is a two-force member ΣM C = 0: ΣFx = 0: ΣFy = 0: (12 ft ) FBE + (10.8 ft )( 5 kips ) − (18 ft )( 4.5 kips ) = 0 FBE = 2.25 kips W C x = 2.25 kips W Cx + 2.25 kips − 4.5 kips = 0 C y − 5 kips = 0 C y = 5.00 kips Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. W

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