COSMOS Chapter 8 Solution 130 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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192

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 130. FBD motor and mount: Impending belt slip, cw rotation µs β T2 = T1e sin α2 ( 0.40π ) T2 = T1e sin18° = 58.356T1 ΣM D = 0: (12 in.)(175 lb ) − (13 in.) T1 − ( 7 in.) T2 =0 2100 lb = 13 in. + ( 7 in.)( 58.356 )  T1 T1 = 4.9823 lb, T2 = 58.356T1 = 290.75 lb FBD drum at B: ΣM B = 0: M B + ( 3 in.)( 4.9823 lb − 290.75 lb ) = 0 M B = 857 lb ⋅ in. (Compare to 421 lb ⋅ in. using flat belt, Problem 8.107) Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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