COSMOS Chapter 9 Solution 168 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2023
Views:

52

Pages:

1
Author:

Nicole Wang

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 168. I x = 9.8821 × 10−3 lb ⋅ ft ⋅ s 2 From Problem 9.147: I y = 11.5344 × 10−3 lb ⋅ ft ⋅ s 2 I z = 2.1878 × 10−3 lb ⋅ ft ⋅ s 2 I xy = 0.48776 × 10−3 lb ⋅ ft ⋅ s 2 Problem 9.151: I yz = 1.18391 × 10−3 lb ⋅ ft ⋅ s 2 I zx = 2.6951 × 10−3 lb ⋅ ft ⋅ s 2 Now λ x = λ y = λz and λx2 + λ y2 + λz2 = 1 3λx2 = 1 Therefore, λx = λ y = λz = or 1 3 Equation 9.46 I OL = I xλx2 + I y λ y2 + I z λz2 − 2I xy λxλ y − 2I yz λ y λz − 2I zxλz λx 2 2 2   1   1   1   1  1  = 9.8821 + 11.5344 + 2.1878      − 2 ( 0.48776 )      3  3  3  3  3     1  1   −3 2   − 2 ( 2.6951)     × 10 lb ⋅ ft ⋅ s 3 3 3 3        − 2 (1.18391)  = 4.95692 × 10−3 lb ⋅ ft ⋅ s 2 or I OL = 4.96 × 10−3 lb ⋅ ft ⋅ s 2

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