COSMOS Chapter 4 Solution 105 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
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45

Pages:

2
Author:

palangresq3v

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 105. Free-Body Diagram: First note W AB = (5 lb/ft )(2 ft ) = 10 lb WBC = ( 5 lb/ft )( 4 ft ) = 20 lb From free-body diagram. of pipe assembly ΣFy = 0: TA + TC + TD − 10 lb − 20 lb = 0 ∴ TA + TC + TD = 30 lb (1) ΣM x = 0: (10 lb )(1 ft ) − TA ( 2 ft ) = 0 or TA = 5.00 lb TC + TD = 25 lb From Equations (1) and (2) (2) (3) ΣM z = 0: TC ( 4 ft ) + TD ( amax ) − 20 lb ( 2 ft ) = 0 or ( 4 ft ) TC + TD amax = 40 lb ⋅ ft (4) continued COSMOS: Complete Online Solutions Manual Organization System Using Equation (3) to eliminate TC 4 ( 25 − TD ) + TD amax = 40 amax = 4 − or 60 TD By observation, a is maximum when TD is maximum. From Equation (3), (TD )max occurs when TC = 0. Therefore, (TD )max = 25 lb and amax = 4 − 60 25 = 1.600 ft Results: (a) amax = 1.600 ft (b) TA = 5.00 lb TC = 0 TD = 25.0 lb

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