University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

279

Pages:

1
Author:

diamundgalx45p

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 130. FBD BCD: d = 0.24 m ΣFy = 0: 0.100 m = 0.1875 m 0.128 m (80 N ) sin 45° − By =0 By = 40 2 N ΣM C = 0: ( 0.100 m )(80 N ) cos 45° + ( 0.1875 m )( 80 N ) sin 45° ( + ( 0.24 m ) 40 2 N ) − ( 0.128 m ) Bx = 0 Bx = 233.13 N FBD AB: ΣM A = 0: ( 0.2 m ) ( 40 ) 2 N − ( 0.15 m )( 233.13 N ) = 0 M = 46.3 N ⋅ m. Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. !