COSMOS Chapter 8 Solution 136 | Michigan State University - Edubirdie

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2021
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 136. FBD window: ( ) T = ( 2 kg ) 9.81 m/s 2 = 19.62 N = ΣFx = 0: N A − ND = 0 FA = µ s N A Impending motion: ΣM D = 0: ( W = ( 4 kg ) 9.81 m/s NA = ) = 39.24 N ΣFy = 0: N A = ND FD = µ s N D ( 0.36 m )W − ( 0.54 m ) N A − ( 0.72 m ) FA W = 2 W 2 =0 3 N A + 2µ s N A 2 2W 3 + 4µ s FA − W + T + FD = 0 FA + FD = W − T = Now Then W 2 FA + FD = µ s ( N A + N D ) = 2µ s N A W 2W = 2µ s 2 3 + 4µ s or Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. µ s = 0.750 W

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